Electrical Engineering

Power Factor Correction (Capacitor Bank)

Calculate reactive power compensation and required capacitor bank size to improve power factor from current to target value.

Units:
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💡Grid operators typically penalise power factors below 0.90. Improving cos φ from 0.75 to 0.95 reduces apparent current by 21%, cutting cable losses and transformer loading significantly. Use detuned capacitor banks (filter reactors) to avoid resonance with harmonics.
Qc [kVAr] = P × (tan φ₁ − tan φ₂) | C [µF] = Qc × 10⁶ / (2π × f × U²)
P [kW] Q S φ cos φ = P/S
Input
Apparent power S iTotal apparent power of the installation in kVA. S = U × I.
kVA
Current power factor iCurrent power factor of the installation (measured or from utility bill).
Target power factor iDesired power factor after compensation. Recommended: 0.95–0.98.
Line voltage iThree-phase line voltage in Volts.
V
Frequency iNetwork frequency: 50 Hz (Europe) or 60 Hz (US/Canada).
Hz
Result
Active power P [kW]
Current reactive power Q₁ [kVAr]
Target reactive power Q₂ [kVAr]
Compensation required Qc [kVAr]
Capacitor per phase (Δ) [µF]
Current reduction [%]
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