Electrical Engineering

Voltage Drop — Single Phase AC

Calculate voltage drop in single-phase AC cables from current or power, cable length and conductor cross-section.

Units:
in LinkedIn
💡Maximum permissible voltage drop per IEC 60364: 3% for lighting circuits (6.9V at 230V) and 5% for motor circuits (11.5V at 230V). Excessive voltage drop causes motor overheating, reduced torque and equipment malfunction.
Uv = 2 × ρ × L × I × cos(φ) / A [ρ_Cu = 0.01754 Ω·mm²/m @ 20°C]
cross-section A [mm²] Ø U₁ U₂ ΔU
Input
Cable length (one way) iOne-way cable length in metres. The return conductor is automatically included (factor 2).
m
Current I iCurrent through the cable in Ampères.
A
Conductor cross-section iConductor cross-section in mm². Standard: 0.75 | 1.0 | 1.5 | 2.5 | 4 | 6 | 10 | 16 mm².
mm²
Power factor cos φ iPower factor. 1.0 = pure resistive load. Motors typically 0.75–0.92.
Supply voltage iAC supply voltage in Volts.
V
Conductor material iConductor material. Copper ρ=0.01754, Aluminium ρ=0.02830, Iron ρ=0.12048 Ω·mm²/m.
Result
Voltage drop Uv [V]
Percentage drop [%]
Residual voltage [V]
IEC 60364 assessment
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